Question

A committee of 4 must be chosen from 3 women and 4 men.calculate

1. In how many ways the committee can be chosen.

2. In how many ways 2 men and 2 women can be chosen

3. Probability that the committee consists of 2 men and 2 women

4. Probability that the committee. consists of atleast 2 women.

Answer 1

1. no restrictions, number of committees
= C(7,4) = 35

2. 2 men and 2 women,
number is C(4,2) x C(3,2)
= 6(3)
= 18

3. same set-up as #2, you try it

4. at least 2 women
---> 2 women, 2 men + 3women, 1 man
= ...

let me know what you got

Answer 2

Truee have succeeded