Asked by aayush
The parelel side of a trapezium is 65m 40m its nonparallel sides are 39 m56m find the area
Answers
Answered by
Reiny
make a sketch.
On mine I sketched a rectangle of side 40 and height h, with two right-angled triangles on each end
On the left I had a hypotenuse of 39 , a height of height, and a base of x
On the right , I had a hypotenuse of 56, a height of h and a base of 25-x
so h^2 + x^2 = 39^2 and h^2 + (25-x)^ = 56^2
both can be solved for h^2 and the results equated to get:
39^2 - x^2 = 56^2 - (25-x)^2
solve for x
once you have x, you can find h, the height of the parallelogram (note correct spelling)
area of parallelogram
= (1/2)(h)(40+65)
you do the button pushing
On mine I sketched a rectangle of side 40 and height h, with two right-angled triangles on each end
On the left I had a hypotenuse of 39 , a height of height, and a base of x
On the right , I had a hypotenuse of 56, a height of h and a base of 25-x
so h^2 + x^2 = 39^2 and h^2 + (25-x)^ = 56^2
both can be solved for h^2 and the results equated to get:
39^2 - x^2 = 56^2 - (25-x)^2
solve for x
once you have x, you can find h, the height of the parallelogram (note correct spelling)
area of parallelogram
= (1/2)(h)(40+65)
you do the button pushing
Answered by
Anonymous
1764
Answered by
Akshay
1764m2
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