Asked by Kimberlee
find three consecutive even integers that 3 times that 1st is equal to the 2nd added to the 3rd plus 38
Answers
Answered by
Reiny
even integers are 2 apart, so if we let
the first be n
the 2nd be n+2
the rd be n+4
now just translate the English into Math
"3 times the 1st " ---- 3n
"is equal to" ---> =
"2nd added to the 3rd plus 38" ---> (n+2) + (n+4) + 38
3n = n+2 + n+4 + 38
solve for n
the first be n
the 2nd be n+2
the rd be n+4
now just translate the English into Math
"3 times the 1st " ---- 3n
"is equal to" ---> =
"2nd added to the 3rd plus 38" ---> (n+2) + (n+4) + 38
3n = n+2 + n+4 + 38
solve for n
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