Asked by kira
Half Robert’s piece of wire is equal to 2/3 of Maria’s wire. The total length of their wires is 10
feet. How much longer is Robert’s wire than Maria’s?
feet. How much longer is Robert’s wire than Maria’s?
Answers
Answered by
Reiny
length of Roberts wire --- x
length of Maria's wire ---- 10-x
x = (2/3)(10-x)
times 3
3x = 2(10-x)
3x = 20 - 2x
5x = 20
x = 4
take over
length of Maria's wire ---- 10-x
x = (2/3)(10-x)
times 3
3x = 2(10-x)
3x = 20 - 2x
5x = 20
x = 4
take over
Answered by
libber
3/4
Answered by
Clarissa
5 more
Answered by
Elise
10/7
Answered by
Anonymous
27/3
Answered by
Stephen
4 is not the answer and the first problem in the above happens in the first line. X= the total length of R's wire. R's wire isn't equal to 2/3 of M's. Half of R's is = to 2/3 M.
so the problem should go as such.
.5 x= 2/3(10-x)
multiply both sides by 3
1.5x=2(10-x)
1.5x=20-2x
3.5x=20
20/3.5= 5.714=x
Now to check our answer 5.714/2=2.857=half of R's length.
10-5.714=4.286
4.286/3=1.428
1.428x2=2.857
2.857x2=4.286
4.286+5.714=10
so the problem should go as such.
.5 x= 2/3(10-x)
multiply both sides by 3
1.5x=2(10-x)
1.5x=20-2x
3.5x=20
20/3.5= 5.714=x
Now to check our answer 5.714/2=2.857=half of R's length.
10-5.714=4.286
4.286/3=1.428
1.428x2=2.857
2.857x2=4.286
4.286+5.714=10
Answered by
Stephen
Sorry, that should read 2.857x2=5.714
4.285= the length of M's wire
4.285= the length of M's wire
Answered by
ka
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no
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