Asked by Larry
messed up on last question. heres the actual one.
Aretha has $0.85 in nickels and dimes. She has 2 more nickels than dimes. How many nickels and imes does she have?
Need a formula for this problem.
These word problems are so hard. Help please!
I may have several more other questions after this.
thanks
Aretha has $0.85 in nickels and dimes. She has 2 more nickels than dimes. How many nickels and imes does she have?
Need a formula for this problem.
These word problems are so hard. Help please!
I may have several more other questions after this.
thanks
Answers
Answered by
anonymous
Aretha has 7 nickles(35 cents)and 5 dimes(50 cents).7*5=35,5*10=50, and 35+50=85 cents!
Answered by
drwls
Let N be the number of nickels
Let D be the number of dimes
N = D + 2
5N + 10 D = 85 (cents)
Now substitute to get rid of N
5(D+2) + 10 D = 85
15 D = 75
D = 5
N = 7
If you don't know algebra yet, you could solve this by trial and error, starting wth 8 dimes and 10 nickels (which is more than 85 cents), and then reducing (D,N) to (7,9),(6,8) etc until you find a combination that equals 85 cents.
Let D be the number of dimes
N = D + 2
5N + 10 D = 85 (cents)
Now substitute to get rid of N
5(D+2) + 10 D = 85
15 D = 75
D = 5
N = 7
If you don't know algebra yet, you could solve this by trial and error, starting wth 8 dimes and 10 nickels (which is more than 85 cents), and then reducing (D,N) to (7,9),(6,8) etc until you find a combination that equals 85 cents.
Answered by
anonymous
You should start off where there are 2 more nickles than dimes. For, example 10 nickles & 8 dimes, 8 nickles and 6 dimes!
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