Asked by Ashley
A fish tank has dimensions 46 cm wide by 1.0 m long by 0.70 m high. If the filter should process all the water in the tank once every 3.0 h, what should the flow speed be in the 3.0-cm-diameter input tube for the filter?
I tried using Q=v/t and Q=vA...
V=0.46m*1m*0.7m=0.322m^3
t=3hours=10800 seconds
A=3.14*0.03^2=.0028
Q=v/t=0.322/10800=2.96*10^-5/0.0028
Q=vA -> v=Q/A=2.96*10^-5/0.0028= 0.010479
so, v=~0.0105 m^3/s right? but it keeps coming up as wrong...what am i doing wrong??
I tried using Q=v/t and Q=vA...
V=0.46m*1m*0.7m=0.322m^3
t=3hours=10800 seconds
A=3.14*0.03^2=.0028
Q=v/t=0.322/10800=2.96*10^-5/0.0028
Q=vA -> v=Q/A=2.96*10^-5/0.0028= 0.010479
so, v=~0.0105 m^3/s right? but it keeps coming up as wrong...what am i doing wrong??
Answers
Answered by
Damon
A=3.14*0.03^2=.0028
!!!!!!!!!!!!!!!!!!!
.03 is DIAMETER
NOT Radius
you want A = pi D^2/4
otherwise you have the right idea
!!!!!!!!!!!!!!!!!!!
.03 is DIAMETER
NOT Radius
you want A = pi D^2/4
otherwise you have the right idea
Answered by
Damon
try 4 times that :)
Answered by
Damon
2.96*10^-5 /(.0028/4)
= .0423 m^3/s
= .0423 m^3/s
Answered by
Anonymous
3.3
Answered by
Gatwech Gach Jock
I need based on necessary steps
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