Question

A fish tank has dimensions 46 cm wide by 1.0 m long by 0.70 m high. If the filter should process all the water in the tank once every 3.0 h, what should the flow speed be in the 3.0-cm-diameter input tube for the filter?

I tried using Q=v/t and Q=vA...

V=0.46m*1m*0.7m=0.322m^3
t=3hours=10800 seconds
A=3.14*0.03^2=.0028

Q=v/t=0.322/10800=2.96*10^-5/0.0028
Q=vA -> v=Q/A=2.96*10^-5/0.0028= 0.010479

so, v=~0.0105 m^3/s right? but it keeps coming up as wrong...what am i doing wrong??

Answer 1

A=3.14*0.03^2=.0028

!!!!!!!!!!!!!!!!!!!
.03 is DIAMETER
NOT Radius
you want A = pi D^2/4
otherwise you have the right idea

Answer 2

try 4 times that :)

Answer 3

2.96*10^-5 /(.0028/4)
= .0423 m^3/s

Answer 4

3.3

Answer 5

I need based on necessary steps