Asked by Sanaya
Calculate the frequency of light associated with the emission from n=5 to n=4 in the hydrogen atom.
I got -7.41 x10^13 Hz, but the answer would make sense if it is positive... So does this mean that when the electrons jump from n=5 to n=4, energy is emitted, but the energy has to change to positive??
Is the answer then
+7.41 x 10^13 Hz?
I got -7.41 x10^13 Hz, but the answer would make sense if it is positive... So does this mean that when the electrons jump from n=5 to n=4, energy is emitted, but the energy has to change to positive??
Is the answer then
+7.41 x 10^13 Hz?
Answers
Answered by
DrBob222
E = R(1/16 - 1/25) and that is a positive number. You probably got a negative number by making it 1/25 - 1/16.
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