Asked by Maddy
A large statue in a crate is being moved. The mass of the statue and the crate is 150 kg. As the statue slides down a ramp inclined at 40.0°, the curator pushes up, parallel to the ramp’s surface, so that the crate does not accelerate. If the statue slides 3 m down the ramp, and the coefficient of kinetic friction between the crate and the ramp is 0.54, calculate the work done on the crate by each of the following: (a) the gravitational force, (b) the curator, (c) the friction force, and (d) the normal force between the ramp and the crate.
So far i figured out that (a) the gravitational force and (d) the normal force do no work on the crate because they are perpendicular to the displacement. I tried to calculate the work done by the (c) friction force by using Fs=m*a=150*0 because there is no acceleration. But i am not sure if this is correct. And i do not know how to figure out the work done by (b) the curator.
Any help would be appreciated, thank you!
So far i figured out that (a) the gravitational force and (d) the normal force do no work on the crate because they are perpendicular to the displacement. I tried to calculate the work done by the (c) friction force by using Fs=m*a=150*0 because there is no acceleration. But i am not sure if this is correct. And i do not know how to figure out the work done by (b) the curator.
Any help would be appreciated, thank you!
Answers
Answered by
Rose
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The statue of Isaac Newton is crated and moved from the Oxford Museum of Natural History and Science for cleaning
same question there
The statue of Isaac Newton is crated and moved from the Oxford Museum of Natural History and Science for cleaning
same question there
Answered by
Henry
Ws = M*g = 150*9.8 = 1470 N.
Fp = 1470*sin40 = 945 N.=Force parallel to the ramp.
Fn = 1470*Cos40 = 1126 N. = Normal force
Fk = u*Fn = 0.54 * 1126 = 608 N. = Force
of kinetic friction.
Fp-Fc-Fk = M*a.
945-Fc-608 = M*0 = 0.
337-Fc = 0.
Fc = 337 N. = Force of the curator.
a. Work = Fg*d = 1470 * 3 = 4410 J.
b. Work = Fc*d = 337 * 3 = 1011 J.
c. Work = Fk*d = 608 * 3 = 1824 J.
d. Work = Fn*d = 1126 * 3 = 3378 J.
Fp = 1470*sin40 = 945 N.=Force parallel to the ramp.
Fn = 1470*Cos40 = 1126 N. = Normal force
Fk = u*Fn = 0.54 * 1126 = 608 N. = Force
of kinetic friction.
Fp-Fc-Fk = M*a.
945-Fc-608 = M*0 = 0.
337-Fc = 0.
Fc = 337 N. = Force of the curator.
a. Work = Fg*d = 1470 * 3 = 4410 J.
b. Work = Fc*d = 337 * 3 = 1011 J.
c. Work = Fk*d = 608 * 3 = 1824 J.
d. Work = Fn*d = 1126 * 3 = 3378 J.
Answered by
Kota
This is wrong
Answered by
Jasmine Merritt
**THIS IS THE RIGHT ANSWER NOT THE ONE ABOVE!**
weight = mg = 150kg*9.8m/s^2 = 1470N
Wgrav = 1470N * sin(40) * 3m = 2835 J
Fparallel = 1470N*sin(40) = 945N
Fnormal = 1470N*cos(40) = 1126N
Fkinetic = 1126N*0.54 = 608N
Wfriction = 608N * 3m * cos(180) = -1824J
Fcurrator = Fparallel - Fkinetic = 945N - 608N = 337N
Wcurrator = 337N * 3m * cos(180)= -1011J
Wnormal = 0, because the normal force is acting perpendicular to the direction of motion
weight = mg = 150kg*9.8m/s^2 = 1470N
Wgrav = 1470N * sin(40) * 3m = 2835 J
Fparallel = 1470N*sin(40) = 945N
Fnormal = 1470N*cos(40) = 1126N
Fkinetic = 1126N*0.54 = 608N
Wfriction = 608N * 3m * cos(180) = -1824J
Fcurrator = Fparallel - Fkinetic = 945N - 608N = 337N
Wcurrator = 337N * 3m * cos(180)= -1011J
Wnormal = 0, because the normal force is acting perpendicular to the direction of motion
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