Asked by Gia

To move a large crate across a rough floor, you push on it with a force F at an angle of 21° below the horizontal, as shown in the figure. Find the force necessary to start the crate moving, given that the mass of the crate is m = 36 kg and the coefficient of static friction between the crate and the floor is 0.67.
Answered by bobpursley
I am not certain which way the force is directed: I assume downward.

force normal=mg+F*sinTheta
frictionforce=mu*forcenormal

to start the motion, F*cosTheta = friction force, solve for F. It's just algebra.
Answered by Justin
236.4+.24F
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