Asked by david agom
A mass of 4kg rest on a rough table with coefficient of force 0.4. Find tje force sufficient to move it horizontally.
Answers
Answered by
Damon
normal force = m g = 4*9.81
friction force = .4 * 4 * 9.81 = answer in Newtons
friction force = .4 * 4 * 9.81 = answer in Newtons
Answered by
david agom
If a force of 10N is neede to move a mass of 2kg resting on a table fine the coefficient of friction. ( take 9.8m/s). Gravity
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.