Question

At t = 0 s,a particle of mass 7.08 kg starts from rest at the origin and moves with a velocity
v = 6.00t^2i(hat) − 6.00tj(hat) + 6.00k(hat) m/s.

1. What is the angular momentum of the particle at t = 0 s


I know angular is calculated from moment of inertia * angular velocity but I'm so confused.

Answer 1

at t = 0
v = 6 k
momentum = (7.08*6) k
now to get angular momentum we need a center
I omega = m V cross R = m V x R
it is at the center (R=0) so its angular momentum about the center is zero.

Answer 2

Okay so for t = 0.850 s I would plug in 0.850 for R?

Answer 3

i meant t