Question
What is the optical purity of a partially racemized product is the calculated specific rotation is -8◦ and the pure enantiomer has a specific rotation of -10◦? Calculate the percentage of each of the enantiomers in the partially racemized product.
I'm very lost. Is this correct?
%ee = -8/-10 x100% =80%
100-80= 20
20/2= 10%
90% (-) enantiomer
10% (+) enantiomer
I'm very lost. Is this correct?
%ee = -8/-10 x100% =80%
100-80= 20
20/2= 10%
90% (-) enantiomer
10% (+) enantiomer
Answers
1*2
im lost tooo0
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