Asked by lin
how to solve for x?
5^x=(25^(2x-1))(125^(4-2x))
5^x=(25^(2x-1))(125^(4-2x))
Answers
Answered by
nile
5^x=(5^2(2x-1))(5^3(4-2x))
5^x=(5^(4x-2))(5^(12-6x))
5^x=5^(4x-2+12-6x)
5^x=5^(-2x+10)
x=-2x+10
3x=10
x=10/3
or 3.3333
or 3.33 with bar on top
5^x=(5^(4x-2))(5^(12-6x))
5^x=5^(4x-2+12-6x)
5^x=5^(-2x+10)
x=-2x+10
3x=10
x=10/3
or 3.3333
or 3.33 with bar on top
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