Asked by shan
jane hits a golf ball on a flat fairway. The ball leaves the ground at a 14.5 degree angle and lands 193 meters away. How long was the ball in the air? How fast was the ball moving when it left the ground?
Answers
Answered by
drwls
V cos14.5 * T = 193
2 (V sin 14.5)^2/g = T
Solve those two equations for V and T.
Shortcut:
The range of 193 m = V^2/g sin (2*14.5)
You can solve that right away for V.
2 (V sin 14.5)^2/g = T
Solve those two equations for V and T.
Shortcut:
The range of 193 m = V^2/g sin (2*14.5)
You can solve that right away for V.