Question
a golfer hits a golf ball which is 30m high infront of a 20m high tree. the ball just passes over the top of the tree. what was the vertical component of the initial velocity of the ball?
Answers
Y^2 = Vo^2 + 2g*h
h = (Y^2-Yo^2)/2g
h = (0-Yo^2)/-19.6 = 30 m.
-Yo^2 = -588
Yo^2 = 588
Yo = 24.2 m/s.
h = (Y^2-Yo^2)/2g
h = (0-Yo^2)/-19.6 = 30 m.
-Yo^2 = -588
Yo^2 = 588
Yo = 24.2 m/s.
Related Questions
Sam hits a golf ball with a five-iron a distance of 120 m horizontally. A tree 45 m high and 35 m in...
A golfer has to hit a ball over a tree that is 12.0 meters high from 40.0 meters away. The ball is h...
A golfer hits a ball off of the ground with an angle of elevation of 10 degrees and an initial velo...
On a flat golf course, a golf ball lies 12m from the base of a lamp post. A golfer hits the ball wit...