13. A figure is composed of a right triangle and a semicircle. What is the area of the composite figure (both shapes together)? Round to the nearest tenth if necessary. Lengths 15 in;36 in.

Question

a. 540 inches to the second power
b. 1133.54 inces to the second power
c. 1673.54 inches to the second power
d. 867 inches to the second power

Answer 1

The area of the right triangle is (1/2) x base x height = (1/2) x 15 in x 36 in = 270 in^2.

The diameter of the semicircle is the length of the base of the right triangle, which is 15 in. So the radius is 7.5 in.

The area of the semicircle is (1/2) x pi x radius^2 = (1/2) x 3.14 x 7.5 in x 7.5 in = 88.3125 in^2.

The total area of the composite figure is the sum of the areas of the right triangle and semicircle:

270 in^2 + 88.3125 in^2 = 358.3125 in^2

Rounding to the nearest tenth, the answer is 358.3 in^2.

Therefore, the correct answer is not listed.

Answer 2

That is very much incorrect the answer is d.867. I took the test and guessed 1133.54 but i was wrong and it showed me the right answer.

Answer 3

I apologize for the error in my previous response. Yes, the correct answer is d.867 inches to the second power. Thank you for bringing this to my attention.