Question

Please help me!!! The table below represents the velocity of a car as a function of time:

time Velocity
seconds (m/s)
x f (x)

15 45
22 66
29 87
36 108

The average rate of change of the function between x = 15 to x = 29 is __________m/s2 and represents the car's acceleration

Answer 1

Since acceleration is the derivative of velocity, you have to take the slope between 15 and 29.

f(b)-f(a)/b-a
(87-45)/(29-15)=42/14= 3 m/s2

Answer 2

Since acceleration is the derivative of velocity, you have to take the slope between 15 and 29.

f(b)-f(a)/b-a
(87-45)/(29-15)=42/14= 3 m/s2
That means that 3m/s2 is 3 meters per second