Asked by john

The distance traveled by an object moving in a straight line is given by s = t2 − 2t,
where s is in feet and t is the time in seconds the object has been in motion. How long
(to the nearest tenth) will it take the object to move 48 feet?

Answers

Answered by Steve
just solve

t^2-2t = 48
t^2-2t-48 = 0
(t-8)(t+6) = 0

I expect you can take it from there, no?
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