Asked by john
The distance traveled by an object moving in a straight line is given by s = t2 − 2t,
where s is in feet and t is the time in seconds the object has been in motion. How long
(to the nearest tenth) will it take the object to move 48 feet?
where s is in feet and t is the time in seconds the object has been in motion. How long
(to the nearest tenth) will it take the object to move 48 feet?
Answers
Answered by
Steve
just solve
t^2-2t = 48
t^2-2t-48 = 0
(t-8)(t+6) = 0
I expect you can take it from there, no?
t^2-2t = 48
t^2-2t-48 = 0
(t-8)(t+6) = 0
I expect you can take it from there, no?
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