Asked by Kiley
The UNBALANCED equation is: Zn + HCl –] ZnCl2 + H2 How many milliliters of a 0.48 M HCl solution are needed to react completely with 7.4 g of zinc to form zinc(II) chloride? Answer in units of mL.
7.4/100.84g*2 mol
7.4/100.84g*2 mol
Answers
Answered by
DrBob222
Not quite it.
mols Zn = grams/molar mass (Zn, not ZnCl2)
Convert mols Zn to mols HCl. That 2 is right.
Then M HCl = mols HCl/L HCl. You know mols and M, solve for L ad convert to mL.
mols Zn = grams/molar mass (Zn, not ZnCl2)
Convert mols Zn to mols HCl. That 2 is right.
Then M HCl = mols HCl/L HCl. You know mols and M, solve for L ad convert to mL.
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