Asked by jyoti

By selling at Rs 77, some 2 1/4% shares of face-value Rs 100 and investing the proceeds in 6% shares of face value Rs 100, selling at Rs 110 a person increased his income by Rs 117 per annum. How many shares did he sell?

Two pipes running together can fill a cistern in 11 1/9 minutes. If one pipe takes 5 minutes more than the other to fill the cistern, find the time in which pipe would fill the cistern.

Please help me to find..

Answers

Answered by Steve
If he sold x shares, then he'd have made
.0214x

By selling them, he received 77x
Investing them, he bought

77x/100 shares of 6% shares.

77x/100 * .06 = .0462x

So, he increased his income by
(.0462-.0214)x = 117
x = Rs 4717.74

If the slow pipe takes x minutes, then we have

1/x + 1/(x+5) = 1/(11 1/9)
Now just solve for x and then x+5
Answered by Reiny
I am not familiar with the stock-market system in your country, but I can do the 2nd question

rate of first pipe = 1/x cisterns/min
rate of 2nd pipe = 1/(x+5) cisterns/min

combined rate = 1/x + 1/(x+5) = (x+5 + x)/(x(x+5))
but that is 11 1/9 min or 100/9 minutes

1/[(2x+5)/(x(x+5))] = 100/9
(2x+5)/(x(x+5)) = 9/100
9x^2 + 45x = 200x + 500
9x^2 - 155x - 500 = 0

it factors!
(x-20)(9x + 25) = 0
x = 20 or a negative, which is no good

so one pipe alone would take 20 minutes, the other 25 minutes
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