Asked by fiz
Two horses pull horizontally on ropes attached to a tree stump (Fig. 3). Each horse pulls with a force of magnitude F. If the angle between the two ropes is 126O, what is the resultant force?
Answers
Answered by
Henry
Fr = F[0o] + F[126o] =
F + F*Cos126 + (F*sin126)i =
F - 0.588F + 0.809Fi=0.412F + 0.809i.
Tan A = 0.809F/0.412F = 1.96359.
A = 63o N. of E. = 63o CCW.
Fr = 0.809F/sin63 = 0.908F[63o]
F + F*Cos126 + (F*sin126)i =
F - 0.588F + 0.809Fi=0.412F + 0.809i.
Tan A = 0.809F/0.412F = 1.96359.
A = 63o N. of E. = 63o CCW.
Fr = 0.809F/sin63 = 0.908F[63o]
Answered by
Hodan Ali Yusuf
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Answered by
Student zone
Two horses pull horizontally on ropes attached to a tree stump . Each horse pulls with a force of magnitude F. If the angle between the two ropes is 126O, what is the resultant force?
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