Question
Three people pull horizontally on ropes attached to a post, as shown in the figure.(Figure 1) The total force that they exert on the post is zero. One of them pulls directly north with F1 = 500 N . Another pulls with F2 = 400 N in a direction 60.0∘ west of north. Find the magnitude and direction of the force F⃗ 3 exerted by the third person so that the sum of the three forces is zero.
Answers
500[90o] + 400[90o+60o] + F3 = 0
500i -346.41+200i + F3 = 0.
-346.41 + 700i + F3 = 0.
F3 = 346.41 - 700i = 781N.[-63.7o] =
781N.[63.7o] S. of E.
500i -346.41+200i + F3 = 0.
-346.41 + 700i + F3 = 0.
F3 = 346.41 - 700i = 781N.[-63.7o] =
781N.[63.7o] S. of E.
hehe
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