Question

1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation.
(2,-2);y=-x-2
A.y=-2x
B.y=2x ********
C.y=1/2x
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation.
(2,-1);y=-3/2x-6
A.y=-3/2x+1
B.y=-3/2x-1
C.y=-3/2x+2 *********
D.y=-3/2x+4
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation.
(4,2);x=-3
A.y=2
B.y=2x+4
C.y=4x**************
D.y=4

Answer 1

Is anyone available to check these for me?

Answer 2

#1
Since your new line is to be parallel to y = -x - 2
then it must clearly start as y = -x ...... as well
let new one be y = -x + b, but (2,-2) is on it, so
-2 = -2) + b
b = 0
new one is y = -x

#2, correct
#3, the given line x = -3 is a vertical line
so the vertical line passing through (4,2) must be
x = 4, which is none of the given choices
TYPO!