Question
Two vectors F1 and F2 with magnitude F1=42N and F2=70N and where angle1=83 and angle2= 300. The angles are measures from the positive x axis with the counter-clockwise angular direction as positive. What is the magnitude of the resultant vector where F=F1+F2?
Answers
Henry
F = 42N[83o] + 70N[300o].
X = 42*Cos83 + 70*Cos300 =
Y = 42*sin83 + 70*sin300 =
Tan A = Y/X, A = ?
F = X/Cos A, or F = Y/sin A.
X = 42*Cos83 + 70*Cos300 =
Y = 42*sin83 + 70*sin300 =
Tan A = Y/X, A = ?
F = X/Cos A, or F = Y/sin A.