Asked by Madi
A block of mass 4 kg, which has an initial
speed of 2 m/s at time t = 0, slides on a
horizontal surface.
Find the magnitude of the work that must
be done on the block to bring it to rest.
Answer in units of J.
If a constant friction force of magnitude
5 Newtons is exerted on the block by the surface,
find the magnitude of the acceleration of
the block.
Answer in units of m/s^2
How far does the block slide before it comes
to rest?
Answer in units of m
speed of 2 m/s at time t = 0, slides on a
horizontal surface.
Find the magnitude of the work that must
be done on the block to bring it to rest.
Answer in units of J.
If a constant friction force of magnitude
5 Newtons is exerted on the block by the surface,
find the magnitude of the acceleration of
the block.
Answer in units of m/s^2
How far does the block slide before it comes
to rest?
Answer in units of m
Answers
Answered by
Damon
Kinetic energy = (1/2) m v^2
= (1/2)(4)(4)
= 8 joules
so you need 8 Joules to stop it
F = m a
5 = 4 a
a = 5/4 m/s^2 = 1.25 m/s^2
5 x = 8
x = 8/5 = 1.6 meter
= (1/2)(4)(4)
= 8 joules
so you need 8 Joules to stop it
F = m a
5 = 4 a
a = 5/4 m/s^2 = 1.25 m/s^2
5 x = 8
x = 8/5 = 1.6 meter
Answered by
Damon Is wrong
First part.
=(1/2)(4)(2)(2)
=(1/2)(4)(2)(2)
Answered by
^ this dude is stupid
(1/2)(4)(2)(2) is the same as (1/2)(4)(4)
Answered by
Bob
Woah
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