Asked by anonymous
A chameleon extends its tongue to capture a tasty insect. The tongue accelerates at 33 m/s2 for 0.12 seconds to make the capture. what is the speed of the chameleons tongue when it grabs the insect?
Answers
Answered by
Damon
v = a t
= 33 (.12)
= 33 (.12)
Answered by
anonymous
so the answer is v= 3.96?
Answered by
anonymous
the winner of the drag race was traveling with a speed of 140.3 m/s (313.9 mph) at the end of the quarter mile course the car started from rest and had an average acceleration of 30.4 m/s^2. what was the winning time for this race
v=140.3 m/s
a=30.4 m/s^2
t=?
140.4/30.4= 4.6 m/s
v=140.3 m/s
a=30.4 m/s^2
t=?
140.4/30.4= 4.6 m/s
Answered by
anonymous
three cars accelerate while moving in the positive direction rank the cars in order of increasing acceleration from most negative to most positive.
*car 1 speeds up from 25 m/s to 35 m/s in 10 sec
* car 2 speeds up from 0 to 30 m/s in 15 sec
*car 3 slows down from 32 m/s to 12 m/s in 5 sec
answer 3,2,1???
*car 1 speeds up from 25 m/s to 35 m/s in 10 sec
* car 2 speeds up from 0 to 30 m/s in 15 sec
*car 3 slows down from 32 m/s to 12 m/s in 5 sec
answer 3,2,1???
Answered by
Damon
1/4 mile = 402 meters
average speed = (final speed + original speed)/2 if acceleration is constant
v = 140.3/2
= 70.15 m/s
time = distance/speed = 402/70.15 = 5.73 seconds
check
v end = 0 + 30.4 (5.73)?
174 not really
============================
car 1 a = 10/10 = 1
car 2 a = 0/15 = 2
car 3 a = -20/5 = -4
so 3 , 1 , 2
Answered by
anonymous
i don't understand how u did this??
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