Question

Two numbers are such that twice the greater number exceeds twice the smaller one by 18 and 1/3 of the smaller and 1/5 of the greater numbers are together 21.The numbers are:

Answer 1

Let the numbers be x and y, with x < y

2y = 2x+18
x/3 + y/5 = 21

Now just solve as usual.

Answer 2

x = 36
y = 45

Answer 3

Full qstion slve ksa o ga

Answer 4

Let greater number is 'x'
Smaller number be 'y
Given,greater number exceeds twice the smaller i.e 2x-2y=18...........1
1/3 of smaller and 1/5 of greater i.e 1/3×y+1/5×x=21 this is convert as 3x+5y=315......2
By solving 1 and 2 we get x=45 and y=36
I hope it will help u ☺️

Answer 5

Sorry to say but this was not helpful... Because this answer is not with full explanation so it was very difficult to understand