m + n + x = 45
x = n + 5 so n = (x-5)
x = 2 m so m = x/2
x/2 + x-5 + x = 45
2.5 x = 50
25 x = 500
x = 20
n = x-5 = 15
m = x/2 = 10
1). Sum of three numbers is 45. One number is five more than the second number.It is also twice the third.Find the numbers.
2).Perimeter of quadrilateral is 52in. Longest side is is three times as long as the shortest side. The other two sides are equally long and are 5 in. longer than the shortest side. Find length of all four sides.
2 answers
L = 3 s
a = b = s+5
perimeter = L + s + a + b = 52
3 s + s + s + 5 + s + 5 = 52
6 s + 10 = 52
6 s = 42
s = 7 etc
a = b = s+5
perimeter = L + s + a + b = 52
3 s + s + s + 5 + s + 5 = 52
6 s + 10 = 52
6 s = 42
s = 7 etc
1 answer