Asked by Anonymous
Calculate the molarity of a solution prepared by dissolving 10.0 grams of NaOH and then diluting the solution to 500mL.
Answers
Answered by
Anonymous
10.0gNaOH x (1moleNaOH / 39.99711gNaOH) = .250moleHaOH
.250moleNaOH / .500L = .500M
Is this right?
.250moleNaOH / .500L = .500M
Is this right?
Answered by
Yosef
The molarity of urea in a solution prepared by dissolving 16 g of urea (MW = 60.0 g/mol) in 39g of H2O is M. The density of the .solution is 1.3 g/mL 0.11 .a O 6.3 .b O 3.7 .C O 6.8 .d o 0.16 .e O
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