Asked by Anonymous
Let f(x)= abs of negative abs of x + pi/2 close abs and g(x)= abs of cosx.
the wording might be confusing so here is another description of the equation (the "vertical line" that I refer to is the line you draw as you draw the absolute value sign...for example "line x line" means that x is enclosed by two vertical lines...abs of x....
So here is the description of f(x):
line, negative sign, line, x, line, plus sign, pi/2, line
a)Find the area of f(x) and g(x).
b)Find the volum of solid obtained by spinning the shape from part a) around the x- axis. when x= 3pi/2?
the wording might be confusing so here is another description of the equation (the "vertical line" that I refer to is the line you draw as you draw the absolute value sign...for example "line x line" means that x is enclosed by two vertical lines...abs of x....
So here is the description of f(x):
line, negative sign, line, x, line, plus sign, pi/2, line
a)Find the area of f(x) and g(x).
b)Find the volum of solid obtained by spinning the shape from part a) around the x- axis. when x= 3pi/2?
Answers
Answered by
Steve
all those words!
f(x) = |x + π/2|
g(x) = |cos x|
Not sure what you mean in part (a). f(x) and g(x) intersect in a single point: (-π/2,0)
See the graphs at
http://www.wolframalpha.com/input/?i=plot+y%3D|x%2B%CF%80%2F2|%2C+y%3D|cos+x|
Maybe I misread your text.
f(x) = |x + π/2|
g(x) = |cos x|
Not sure what you mean in part (a). f(x) and g(x) intersect in a single point: (-π/2,0)
See the graphs at
http://www.wolframalpha.com/input/?i=plot+y%3D|x%2B%CF%80%2F2|%2C+y%3D|cos+x|
Maybe I misread your text.
Answered by
Reiny
Steve, I plotted the function the way it was originally stated and it showed a giant W along with the |cosx|
http://www.wolframalpha.com/input/?i=plot+y+%3D+%7C+-+%7Cx%7C+%2B+%CF%80%2F2+%7C+%2C+y+%3D+%7Ccos%28x%29%7C
The "solid" still needs a domain, and not well defined
http://www.wolframalpha.com/input/?i=plot+y+%3D+%7C+-+%7Cx%7C+%2B+%CF%80%2F2+%7C+%2C+y+%3D+%7Ccos%28x%29%7C
The "solid" still needs a domain, and not well defined
Answered by
Steve
yeah, i misread f(x)
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