Asked by Cody

For how many different negative values of x is √x+2001 an integer?
A) 42
B) 43
C) 44
D) 45

A lot to list out, any way to find it faster??

Answers

Answered by Steve
clearly, -2001 <= x <= 0
Thus, 0 <= x+2001 <= 2001
So, how many numbers between 0 and 2001 are squares?

√2001 = 44.7
So, There are 45 numbers such that 0 <= x <= 44, meaning that 0 <= x^2 <= 2001
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