Asked by anonymous
what is the value of "x" when y=0:
8x^2-x-5=y
eight times x squared minus x minus five equals y
8x^2-x-5=y
eight times x squared minus x minus five equals y
Answers
Answered by
bobpursley
Use the quadratic equation:
x=(1+-sqrt(1+160))/16
check that, I did it in my head.
Answered by
taz manian
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