Question

A projectile is launched at an angle of 20.0 degrees above the horizontal with an initial speed of 88.1 m/s. The maximum height reached by the projectile will be ____ m.

Answer 1

Vi = 55.1 sin 20

v = Vi - 9.81 t
v = 0 at top
so
t = Vi/9.81 at top

use that in
h = Vi t - 4.9 t^2