Asked by sam
please po help me.
A chimney projects 6 feet above the roof. At a point 10 feet 8 inches down the roof from the base of the chimney,the chimney subtends an angle of 17°40' . find the angle at which the roof is inclined to the horizontal.
A chimney projects 6 feet above the roof. At a point 10 feet 8 inches down the roof from the base of the chimney,the chimney subtends an angle of 17°40' . find the angle at which the roof is inclined to the horizontal.
Answers
Answered by
Steve
draw a diagram. extend the chimney downward to where it meets a horizontal line drawn from the point Q 10'8" down the roof. Label
T = top of chimney
B = bottom of chimney
PQ = base of right triangle TPQ.
using the law of sines,
6/sin17°40' = 10'8"/sinT
sinT = 10.666*sin17°40'/6 = 0.5395
T = 32.65°
So, in triangle TBQ, angle B = 129.68°
Thus, the angle of the roof (BQP) is
90-(180-129.68) = 39.68°
Call it 40°
T = top of chimney
B = bottom of chimney
PQ = base of right triangle TPQ.
using the law of sines,
6/sin17°40' = 10'8"/sinT
sinT = 10.666*sin17°40'/6 = 0.5395
T = 32.65°
So, in triangle TBQ, angle B = 129.68°
Thus, the angle of the roof (BQP) is
90-(180-129.68) = 39.68°
Call it 40°
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.