Asked by yung

2. A 500 mL saturated silver carbonate solution at 5¢XC is treated with hydrochloric acid to decompose the compound.
Ag2CO3(aq) + 2HCl(aq) ¡÷ 2AgCl(s) + CO2(g) + H2O(l)
The carbon dioxide generated is collected in a 19 mL vial and exerts a pressure of 114 mmHg at 25 ¢XC. What is the Ksp of Ag2CO3 at 5¢XC?
(Given: 1 atm = 760 mmHg)
Answered by DrBob222
Ag2CO3(aq) + 2HCl(aq) ¡÷ 2AgCl(s) + CO2(g) + H2O(l)

........Ag2CO3 ==> 2Ag^+ + CO3^2-
I.......solid........0......0
C.......solid.......2x......x
E.......solid.......2x......x

Use PV = nRT and solve for mols CO2 = mols CO3^2-. Then (CO3^2-) = mols/L of the saturated solution of Ag2CO3.
(Ag^+) = 2*(CO3^2-).
Substitute and solve for Ksp. Post your work if you get stuck.
Answered by Anonymous
0.97
Answered by Kong
My answer is 1.24792 x 10^-10
is it correct?
Answered by Kong
Updated, 4.9917x 10^-10?
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