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Let R be the interior of the circle 4x2 + 4y2 −4x = 0.
Evaluate double integral sqrt(x^2+y^2)
9 years ago

Answers

Steve
∫[0,1] ∫[-√(x-x^2),√(x-x^2)] √(x^2+y^2) dy dx

Or, you might find things easier in polar coordinates.
9 years ago

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