Asked by Calculus 3
Let R be the interior of the circle 4x2 + 4y2 −4x = 0.
Evaluate double integral sqrt(x^2+y^2)
Evaluate double integral sqrt(x^2+y^2)
Answers
Answered by
Steve
∫[0,1] ∫[-√(x-x^2),√(x-x^2)] √(x^2+y^2) dy dx
Or, you might find things easier in polar coordinates.
Or, you might find things easier in polar coordinates.
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