Question
A baseball is thrown at an angle of 21
◦
relative
to the ground at a speed of 22
.
7 m
/
s. The ball
is caught 35
.
1474 m from the thrower.
The acceleration due to gravity is
9
.
81 m
/
s
2
.
How long is it in the air?
◦
relative
to the ground at a speed of 22
.
7 m
/
s. The ball
is caught 35
.
1474 m from the thrower.
The acceleration due to gravity is
9
.
81 m
/
s
2
.
How long is it in the air?
Answers
speed = s = 22.7 m/s
Vi = initial vertical component of speed
= 22.7 m/s sin 21
v = Vi - g t
at top v = 0
so going up
t = Vi /9.81
it spends the same time coming down
so
2 t = time in air = 2 Vi/9.81
or
2 t = 2 * 22.7 * sin 21 /9.81
Vi = initial vertical component of speed
= 22.7 m/s sin 21
v = Vi - g t
at top v = 0
so going up
t = Vi /9.81
it spends the same time coming down
so
2 t = time in air = 2 Vi/9.81
or
2 t = 2 * 22.7 * sin 21 /9.81
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