Asked by Lisa
An aqueous solution contains three solutes. One liter contains: 0.200 moles of calcium chloride, 0.150 moles of magnesium chloride, and 0.750 moles of sodium chloride. How many grams of Cl are there per liter of this solution? a. 39.0 g b. 51.4 g c. 78.0 g d. 80.3 g e.103 g
Answers
Answered by
DrBob222
mols CaCl2 = 0.2
mols Cl in CaCl2 = 2x that.
mols MgCl2 = 0.15
mols Cl in MgCl2 = 2x that.
mols NaCl = 0.75
mols Cl in NaCl = 1 x that.
total mols Cl = sum of Cl.
Then grams = mols x atomic mass.
mols Cl in CaCl2 = 2x that.
mols MgCl2 = 0.15
mols Cl in MgCl2 = 2x that.
mols NaCl = 0.75
mols Cl in NaCl = 1 x that.
total mols Cl = sum of Cl.
Then grams = mols x atomic mass.
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