Asked by em-em
4. A 300-ml aqueous solution containing 40 g compound A is to be extracted with ether. The solubility of compound A in either at room temperature is 20 g per 100 ml and in water is 13.3 g per 100 ml. calculate the weight of the compound that would be recovered by extraction with (a) two 150 ml portions of ether and (b) one 300-ml portion of ether.
Answers
Answered by
DrBob222
First, determine K.
K<sub>o/a</sub> = 20/13.3
Then K = (org layer)/(aq layer)
For part b.
Let x = grams in org layer; then 40-x = grams in aq layer. Then
(organic layer) = x/300
(aqueous layer) = (40-x)/300
K = (x/300)/(40-x)/300
Solve for x and 40-x.
For part a use the same set up but go through the equation twice with 150 mL each. Two extractions with half the amount will ALWAYS extract more.
K<sub>o/a</sub> = 20/13.3
Then K = (org layer)/(aq layer)
For part b.
Let x = grams in org layer; then 40-x = grams in aq layer. Then
(organic layer) = x/300
(aqueous layer) = (40-x)/300
K = (x/300)/(40-x)/300
Solve for x and 40-x.
For part a use the same set up but go through the equation twice with 150 mL each. Two extractions with half the amount will ALWAYS extract more.
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