Question

I am given the function P=9e^(-0.9t)
In the funcion form P=(P initial)(a^t) what are the values of P initial and a

P initial is 9
what is a?

Answer 1

e^(-0.9t) = a^t
Take natural logs of both sides
-0.9t = t ln a
ln a = -0.9
a = e^(-0.9) = 0.40657