Ask a New Question

Question

Find the area of the region between the graphs of f(x)=3x+8 and
g(x)=x^2 + 2x+2 over [0,2].

I got 34/3.
9 years ago

Answers

Steve
∫[0,2] (x^2+2x+2) dx
= 1/3 x^3 + x^2 + 2x [0,2]
= 8/3 + 4 + 4
= 32/3

It would be nice for you to show your work...
9 years ago

Related Questions

Find the area of the region bounded by the graphs of y = x2 − 4x and y = x − 4. a) - 4.500 b)... Find the area of the region bounded by the functions f(x) = x^4 and g(x) = |x|. a) 1.3 b) 5.2 c... Find the área of the región bounded by the graphs of y=x, y=-x+4, and y=0 A) 4 B) 2 C) 8 D) no... Find the area of the region bounded by the graphs of y = −x2 + 3x + 4 and y = 4. a) 2.7 b) 4.5... find area of indicated region under the standard normal curve the numbers are -.45 and 2.11 its... Find the area of the region below y=x^2−2x+3 and above y=9 for 3≤x≤5. Area = Find the area of the region bounded by the curve r=sinθ+cosθand lies in the sector 0≤θ≤π Find the area of the region bounded by the graphs of the equations y=cos^2(x), y=sin^2(x), x=-pi/4,... Find the area of the region enclosed between and from to . Hint: Notice that this region consists...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use