f = 4cosθ + 2sin^2θ
= 4cosθ + 2 - 2cos^2θ
f' = -4sinθ + 4cosθsinθ
critical numbers are when f'=0, so
4sinθ(cosθ-1) = 0
so, sinθ=0 or cosθ=1
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Find the critical numbers of the function. (Enter your answers as a comma-separated list. Use n to denote any arbitrary integer values. If an answer does not exist, enter DNE.)
f(θ) = 4 cos θ + 2 sin^2 θ
1 answer
1 answer