Asked by Julia
I don't understand this at all!
use the position equation s=-16t^2 +v0t+s0 to write a function that represents the situation. Find the average rate of change from t1 to t2.
a) An object is thrown upward from a height of 6 feet at a velocity of 64 feet per second.... t1=0 , t2=3
b) An object is thrown upward from ground level at a velocity of 120 feet per second.... t1=3, t2=5
use the position equation s=-16t^2 +v0t+s0 to write a function that represents the situation. Find the average rate of change from t1 to t2.
a) An object is thrown upward from a height of 6 feet at a velocity of 64 feet per second.... t1=0 , t2=3
b) An object is thrown upward from ground level at a velocity of 120 feet per second.... t1=3, t2=5
Answers
Answered by
Predox
rate of change should be (S(t2)-S(t1))/(t2-t1). unless there is something more complicated which I am missing. Replace the variables with what you have and see what you get. Hope it helps.
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