Asked by shehzad

a man leaves half of his property to his wife.one third to his son and the remaining to his daughter. if the daughter share is 40000. find how much money did he leave. how much did his wife get? what is his son share?
Answered by Steve
clearly the daughter gets 1/6 of the total.
Answered by Anonymous
Total part of property = 10
Wife 1/5
Son 1/3
Thus, daughter= (10/10 )- (1/5+1/3)
= 10/10-8/10
= 2/10

2/10=40000, 1=20000,

10¡Á20000=200000
Answered by Anonymous
Total part of property = 10
Wife 1/5
Son 1/3
Thus, daughter= (10/10 )- (1/5+1/3)
= 10/10-8/10
= 2/10

2/10=40000, 10/2¡Á40000=

10¡Á20000=200000
Answered by Harwinder
19,000
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