Asked by Mark
A sample of Xe takes 75 seconds to effuse out of a container. An unknown gas takes 37 seconds to effuse out of the identical container under identical conditions. What is the most likely identity of the uknown gas
the answer is O2. How do you solve this?
the answer is O2. How do you solve this?
Answers
Answered by
bobpursley
Grahams law look that up in your text.
Xe has molweight of 131
sqrt(xxx/131)=37/75
xxx molecular weight= 131 (37/75)^2
amazing, it is 32 the same as O2.
Xe has molweight of 131
sqrt(xxx/131)=37/75
xxx molecular weight= 131 (37/75)^2
amazing, it is 32 the same as O2.
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