Question
It takes 200. seconds for a sample of carbon dioxide to effuse through a porous plug and 280. seconds for the same volume of an unknown gas to effuse under the same conditions. What is the molar mass of the unknown gas? Enter your answer to 3 significant figures.
Answers
Choose a convenient volume such as 1 L. Then rate CO2 = 1L/200 s = ?
rate unknown = 1L/280 s =
(rate CO2/rate unk) = sqrt(MMunk/MMCO2)
MM = molar mass. Solve for MM unk.l
rate unknown = 1L/280 s =
(rate CO2/rate unk) = sqrt(MMunk/MMCO2)
MM = molar mass. Solve for MM unk.l
39.7
Related Questions
At a particular pressure and temperature, it takes just 2.040 min for a 3.632 L sample of F2 to effu...
It takes 19.6 mins for a 10.0mL sample of an unknown gas to effuse through a pinhole.
A 10.0mL sa...
A sample of Xe takes 75 seconds to effuse out of a container. An unknown gas takes 37 seconds to eff...