Asked by Bobby Funtimes
My teacher wants me to make 5 hard complete the square questions and solve them in front of her to get a %5 bonus mark. Can anyone give me 5 really hard complete the square questions?
Answers
Answered by
Reed
See what you can find here:
http://www.google.com/search?sourceid=navclient&ie=UTF-8&rlz=1T4VRHB_enUS648US649&q=complete+the+square+questions
http://www.google.com/search?sourceid=navclient&ie=UTF-8&rlz=1T4VRHB_enUS648US649&q=complete+the+square+questions
Answered by
Reiny
The hardest type have fractional coefficients that are relatively prime.
I will give you one, and solve it, you pick 4 more like it
y = (2/3)x^2 + (5/7)x - 11/13
factor the coefficient (divide it out) of the x^2 terms from the first two terms, leave the constant term trailing along at the end
= (2/3)(x^2 + (15/14)x ...... ) - 11/13
take 1/2 of the x term coefficient, square it, then add and subtract in side the bracket
= (2/3)(x^2 + (15/14)x + 225/784 - 225/784) - 11/13
the first 3 terms inside the bracket are now a perfect square, write it that way, but don't forget the -225/784 inside the bracket and the -11/13 just hanging on at the end
= (2/3)( (x + 15/28)^2 - 225/784) - 11/13
you now have two terms inside the main bracket, multiply 2/3 by both of them
= (2/3)(x+15/28)^2 - 75/392 - 11/13
all we have to do in combine the two constants at the end, the common denominator is 5096
= (2/3)(x + 15/28)^2 - 975/5096 - 4312/5096
= (2/3)(x + 15/28)^2 - 5287/5087
check my arithmetic
I will give you one, and solve it, you pick 4 more like it
y = (2/3)x^2 + (5/7)x - 11/13
factor the coefficient (divide it out) of the x^2 terms from the first two terms, leave the constant term trailing along at the end
= (2/3)(x^2 + (15/14)x ...... ) - 11/13
take 1/2 of the x term coefficient, square it, then add and subtract in side the bracket
= (2/3)(x^2 + (15/14)x + 225/784 - 225/784) - 11/13
the first 3 terms inside the bracket are now a perfect square, write it that way, but don't forget the -225/784 inside the bracket and the -11/13 just hanging on at the end
= (2/3)( (x + 15/28)^2 - 225/784) - 11/13
you now have two terms inside the main bracket, multiply 2/3 by both of them
= (2/3)(x+15/28)^2 - 75/392 - 11/13
all we have to do in combine the two constants at the end, the common denominator is 5096
= (2/3)(x + 15/28)^2 - 975/5096 - 4312/5096
= (2/3)(x + 15/28)^2 - 5287/5087
check my arithmetic
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.