Question

The function defined below satisfies Rolle's Theorem on the given interval. Find the value of c in the interval (-3, -2) where f'(c)=0.

f(x) = x + 6x-1 , [-3, -2]

Round your answer to two decimal places.

Answer 1

I dislike f(x). It is linear, so cannot satisfy the theorem.

Answer 2

maybe x^2 + 6 x - 1 ?

Answer 3

I thought of that, but in that case, f(-3) ≠ f(-2), so the theorem does not apply.

Answer 4

i think its x+6x^-1