Asked by Ashley
Height of a Projectile.
The height of a projectile is described by the equation:
s(t)=144t-16t^(2)
Where t is in seconds and s(t) is the height of the projectile at time t. Find when the projectile hits the ground.
The height of a projectile is described by the equation:
s(t)=144t-16t^(2)
Where t is in seconds and s(t) is the height of the projectile at time t. Find when the projectile hits the ground.
Answers
Answered by
John
projectile hits the ground when s(t) = 0 meaning the height off the ground is zero.
0 = 144t -16 t^2
Factor out the t:
0 = t(144 -16t)
set each part = to zero
t = 0 the projectile wasn't launched yet
and 144- 16t = 0
solve for t to find out how long the projectile was in the air before hitting the ground.
0 = 144t -16 t^2
Factor out the t:
0 = t(144 -16t)
set each part = to zero
t = 0 the projectile wasn't launched yet
and 144- 16t = 0
solve for t to find out how long the projectile was in the air before hitting the ground.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.