Asked by Aida
Potassium permangenat reacts with sodium oxalate to form carbon dioxide and Mn2+.determine the consentration of a permangenate solution.since the reaction runs in acidic conditions, 25ml of 2 M sulfuric acid was added to 20.00ml of the unknown permangenate solution. It was then titrated with 21.15ml of a 0.111M oxalate solution. what strength was the permangenate solution?
Answers
Answered by
DrBob222
2MnO4^- + 5C2O4^2- ==> 10CO2 + 2Mn^2+
(Note: that doesn't balance all of the equation but the H2SO4, K^+, etc are just spectator ions.)
mols C2O4^2- = M x L = 0.111 x 0.02115=?
Using the coefficients in the balanced equation, convert mols C2O4^2- to mols MnO4^-. That will be ? mols C2O4^2- x (2 mols MnO4^-/5 mols C2O4^2-) = ?
Then M MnO4^- = mols MnO4^-/L MnO4^-. You have mols and L, solve for M.
(Note: that doesn't balance all of the equation but the H2SO4, K^+, etc are just spectator ions.)
mols C2O4^2- = M x L = 0.111 x 0.02115=?
Using the coefficients in the balanced equation, convert mols C2O4^2- to mols MnO4^-. That will be ? mols C2O4^2- x (2 mols MnO4^-/5 mols C2O4^2-) = ?
Then M MnO4^- = mols MnO4^-/L MnO4^-. You have mols and L, solve for M.
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